[Verilog basics] octal and hexadecimal representation of decimal negative numbers

subject ： take -617 Convert to octal and hexadecimal numbers （ Complement code ）

Make a mistake ：（-617）D=（-1151）O=（-269）H

Cause analysis ： If it's a positive number , The above idea is correct , Due to the positive and negative code 、 Inverse code 、 The difference in complement conversion , Therefore, it is wrong to solve negative numbers according to the solution idea of positive numbers .

The right way yes ： First of all, will -617 Express with complement , Then convert it to octal and hexadecimal （ Complement code ） that will do .

notes ： Binary complement to use 16 position .

right key ：（-617）D=（176627）O=（fd97）H

Negative decimal conversion to octal or hexadecimal methods such as （-12）10=（　）8=（　）16

First step ： Convert to binary
　　　1000 0000 0000 1100
The second step ： Complement code , Take the reverse and add one 　　　　　　　　　　　　　　
　　　1111 1111 1111 0100
The third step ： The conversion to octal is Three in one ：（177764）8
　　　 Conversion to Hex is Four in one combination ：（fff4）16

C Language program