SQL implements split

create function [dbo].[Get_StrArrayLength] ( @str varchar(max), – String to split @split varchar(10) – Separator symbol ) returns int as begin declare @location int declare @start int declare @length int – Remove space before and after set @str=ltrim(rtrim(@str)) – Where the separator first appears set @location=charindex(@split,@str) – Set the length of the separated string to 1 set @length=1

while @location<>0 begin set @[email protected]+1 set @location=charindex(@split,@str,@start) set @[email protected]+1 end return @length end

drop function [dbo].[Get_StrArrayStrOfIndex] go create function [dbo].[Get_StrArrayStrOfIndex] ( @str varchar(max), – String to split @split varchar(10), – Separator symbol @index int – Take the first few elements ) returns varchar(1024) as begin declare @location int declare @start int declare @next int declare @seed int declare @pos int if @index<=0 return ” set @str=ltrim(rtrim(@str)) set @start=1 set @next=1 set @pos=1 set @seed=len(@split) set @location=charindex(@split,@str) while @location<>0 and @index>@next and @pos<@index begin set @[email protected][email protected] set @location=charindex(@split,@str,@start) set @[email protected]+1 set @[email protected]+1 end if @location =0 if @pos<>@index return ” else select @location =len(@str)+1 – There are two situations ：1、 There is no delimiter in the string 2、 There is a separator in the string , Jump out of while After the cycle ,@location by 0, The default is that there is a separator after the string . return substring(@str,@start,@[email protected]) end

declare @id varchar(30) select @id=dbo.Get_StrArrayStrOfIndex(‘4321,2223,333,5554′,’,’,2)

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drop function [dbo].[Get_ArrayStrOfName] Go

create function [dbo].[Get_ArrayStrOfName] ( @str varchar(5000), – String to split @split varchar(1), – Separator symbol @itemSplit varchar(1), – Element separator @item varchar(20) – Which element to take ) returns varchar(1024) As Begin declare @location int – Find the position of the substring declare @tempItem varchar(50) – Current item declare @tempItemName varchar(20) – The name of the current item set @str=ltrim(rtrim(@str)) set @tempItem=” set @tempItemName=” while len(@str)>0 Begin —– Found a subitem – set @location=charindex(@split,@str,1) if @location>0 Begin set @tempItem=substring(@str,1,@location-1) set @str=substring(@str,@location+1,len(@str)) End Else Begin set @[email protected] set @str=” end ———- Determine the name of the current sub item ————– set @location=charindex(@itemSplit,@tempItem,1) if @location>0 Begin set @tempItemName=substring(@tempItem,1,@location-1) if @[email protected] return substring(@tempItem,@location+1,len(@tempItem)) End End return ” End Go

declare @id varchar(30) select @id=dbo.Get_ArrayStrOfName(‘[email protected],[email protected],[email protected],[email protected]’, ‘,’, ‘@’, ‘ff’) print @id

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