7-1 positive integer a+b (15 points)

The goal of the question is very simple , It's two positive integers A and B And , among A and B It's all in the range [1,1000]. A little bit of a hassle , The input is not guaranteed to be two positive integers .

Input format ：

Type in on a line to give A and B, They are separated by spaces . The problem is A and B It doesn't have to be a positive integer , Sometimes it can be out of range numbers 、 negative 、 A real number with a decimal point 、 It's even a mess of code .

Be careful ： Let's put... In the input 1 A space is taken as A and B Separation of . Make sure that there is at least one space for the question , also B It's not an empty string .

Output format ：

If the input is really two positive integers , According to the format A + B = and Output . If an input is not satisfactory , Output at corresponding position ?, Obviously at this time and also ?.

Examples 1："> sample input 1：

123 456

sample output 1：

123 + 456 = 579

sample input 2：

22. 18

sample output 2：

? + 18 = ?

sample input 3：

-100 blabla bla...33

sample output 3：

? + ? = ?

Be sure to pay attention to the number beyond the range , Number out of range ！ 

When doing this problem, because PTA In many cases above, although he gave the range of data , But the operation not in this range will not actually care , It leads me to think that all numbers , As a result, there is a test point that cannot be passed .

Ideas ： You can't use shaping to store , So we use character type to store data , Because there must be a space to space a and b Two strings , So the first acceptance we use while((a[i]=getchar())!=' '); To accept the first data , Then our next step is to end after returning , Direct use gets() that will do , After accepting, we need to take out each character and let them form a number , If there is any magical character, we will order one flag, If his value changes , Then we'll print it out ？, At the same time, we have to consider many situations , For example, the first one is not Hello , The first is not to say hello , The second is to say hello , Neither of them is to say hello to these situations . The string we try to define is longer , In case someone really wants to vent on the keyboard （ funny ）, Now we can write code according to this idea .

Code ：

#include <stdio.h>
#include <string.h>
int main(){
    char a[1000],b[1000];
    int i=0,j,flag=0,flag2=0;
    int number1=0,number2=0;
    while(((a[i])=getchar())!=' ')i++;
    gets(b);
    for(j=0;j<i;j++){
        if(a[j]<'0'||a[j]>'9')flag=1;
        else number1=number1*10+a[j]-'0';
    }
    if(number1>1000||number1<1)flag=1;
    if(flag==1)printf("? + ");
    else printf("%d + ",number1);
    for(i=0;i<strlen(b);i++){
        if(b[i]<'0'||b[i]>'9')flag2=1;
        else number2=number2*10+b[i]-'0';
    }
    if(number2>1000||number2<1)flag2=1;
    if(flag2==1)printf("? = ?");
    else if(flag==0&&flag2==0)printf("%d = %d",number2,number1+number2);
    else if(flag2==0&&flag==1)printf("%d = ?",number2);
    
}