7-16 find the set of integers that meet the given conditions

Given no more than 6 The positive integer A, Consider from A The beginning of the continuum 4 A digital . Please output all non repeating numbers composed of them 3 digit .

Input format ：
Enter... On one line A.

Output format ：
The output satisfies the conditions 3 digit , From small to large , Each row 6 It's an integer . Integers are separated by spaces , But there should be no extra spaces at the end of the line .

sample input ：
2

sample output ：
234 235 243 245 253 254
324 325 342 345 352 354
423 425 432 435 452 453
523 524 532 534 542 543

No arrays

#include <stdio.h>

void myprint(int n);

int main()
{
    int x,y;// Lower and upper limits 
    int i, j, k;// Loop variable 
    int n = 1;// Line feed counter 
    scanf("%d", &x);// Enter the minimum number 
    y=x+4;    
    for (i  = x; i < y; i++)// Determine the first number subscript 
    {
        for (j = x; j < y; j++)// Determine the second number subscript 
        {
        	for (k = x ; k < y; k++)// Determine the third number subscript 
            {
                if (i != j && j != k && k != i) // If the three subscripts are not equal to each other, output 
                {
                    printf("%d%d%d", i, j, k);
                    myprint(n);// Newline function 
                    n++;// Counter 
                }
            }
        }
    }
    
    return 0;
}

void myprint(int n)
{
    if (n % 6 == 0)
    {
        printf("\n");// Change careers after six 
    }
    else
    {
        printf(" ");// If you are dissatisfied, output spaces 
    }
}

Using arrays

#include <stdio.h>

void myprint(int n);

int main()
{
    int a[4];// Save consecutive numbers 
    int x;// The smallest number 
    int i, j, k;// Loop variable 
    int n = 1;// Line feed counter 
    scanf("%d", &x);// Enter the minimum number 
    
    for (i = 0; i < 4; i++)	// Save number 
    {
        a[i] = i + x;
    }
    
    for (i  = 0; i < 4; i++)// Determine the first number subscript 
    {
        for (j = 0; j < 4; j++)// Determine the second number subscript 
        {
        	for (k = 0 ; k < 4; k++)// Determine the third number subscript 
            {
                if (i != j && j != k && k != i) // If the three subscripts are not equal to each other, output 
                {
                    printf("%d%d%d", a[i], a[j], a[k]);
                    myprint(n);// Newline function 
                    n++;// Counter 
                }
            }
        }
    }
    
    return 0;
}

void myprint(int n)
{
    if (n % 6 == 0)
    {
        printf("\n");// Change careers after six 
    }
    else
    {
        printf(" ");// If you are dissatisfied, output spaces 
    }
}