Function: find the approximate value of the limit of the ratio of the former term to the latter term of Fibonacci sequence. For example, when the error is 0.0001, the function value is 0.618056.

subject ：

First, explain what Fibonacci sequence is ：

（ Here I quote a picture written by a friend of mine ）

In a nutshell

The first 1 Xiang and di 2 Items for 1, Starting from the back, each item is the sum of the first two items .

A sequence of numbers formed by analogy . 

Code details ：

#include <stdio.h>
#include "math.h"
float fun()
{

	/**********Program**********/
	float f1 = 1, f2 = 1,f3=2,t;//
f1 On behalf of the 1 term ,f2 On behalf of the 2 term ,f3 On behalf of the 3 term 

	while (fabs(f2/f3 - f1/f2) > 0.0001) {
		f1 = f2;
		t = f2 + f3;
		f2 = f3;
		f3 = t;
	}
	return f2/f3;// Method 1

	/*float f1 = 1, f2 = 1, f3;
	float r1 = 2, r2;
	do
	{
		r2 = r1;
		r1 = f1 / f2;
		f3 = f1 + f2;
		f1 = f2;
		f2 = f3;
	} while (fabs(r1 - r2) > 1e-4);
	return r1;*/// Method 2

  /**********  End  **********/

}

int main()

{
	printf("y=%f\n", fun());
}

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