Pat grade B 1009 is ironic (20 points)

Give me an English sentence , Ask you to write a program , Reverse the order of all the words in the sentence .

Input format ：

The test input contains a test case , The total length given in one line does not exceed 80 String . A string consists of several words and spaces , The words are made of English letters （ There is a distinction between case and case ） Composed string , Use... Between words 1 Separate the spaces , Type to make sure there are no extra spaces at the end of the sentence .

Output format ：

The output of each test case takes up one line , Output the sentences in reverse order .

Examples ："> sample input ：

Hello World Here I Come

sample output ：

Come I Here World Hello

Method 1 （ Refer to Qingshen code ）

because PAT It's a single point test , Therefore, this more concise method is produced , The box EOF To determine whether the word has been entered

It should be noted that when entering manually, press ctrl + z End procedure

#include <iostream>
using namespace std;

int main()
{
	int num = 0;
	char ans[90][90];
	while (scanf("%s", ans[num]) != EOF) {
		num++;
	}
	for (int i = num - 1; i >= 0; i--) {
		printf("%s", ans[i]);
		if (i > 0) cout << " ";
	}
	return 0;
}

Method 2 simulation

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string s;
    getline(cin, s);
    char ans[90][90];
    int r = 0, h = 0;
    for (int i = 0; i < s.size(); i++) {
        if (s[i] != ' ') {
            ans[r][h++] = s[i];
        }
        else {
            r++; h = 0;
        }
    }
    for (int i = r; i >= 0; i--) {
        cout << ans[i];
        if (i != 0) cout << " ";
    }
    return 0;
}

#include <iostream>
#include <string>
#include <vector>
using namespace std;

int main()
{
    string s, temp = "";
    getline(cin, s);
    vector<string> ans;
    for (int i = 0; i < s.size(); i++) {
        if (s[i] != ' ') temp += s[i];
        else {
            ans.push_back(temp);
            temp = "";
        }
    }
    ans.push_back(temp);
    for (int i = ans.size() - 1; i >= 0; i--) {
        cout << ans[i];
        if (i != 0) cout << " ";
    }
    return 0;
}

  Method 3   Use c++ Medium istringstream

istringstream Class to execute C++ Style stream input operation

istringstream The original form of the constructor is as follows ：

istringstream::istringstream(string str), Its function is from string object str Read characters in

#include <iostream>
#include <sstream>
#include <string>
#include <vector>
using namespace std;

int main()
{
    string s, word;
    getline(cin, s);
    vector<string>ans;
    istringstream ss(s);
    while (ss >> word) {
        ans.push_back(word);
    }
    for (int i = ans.size() - 1; i >= 0; i--) {
        cout << ans[i];
        if (i != 0) cout << " ";
    }
    return 0;
}