Hdu1228 a + B (map mapping)

 Question：

Problem Description

Read in two less than 100 The positive integer A and B, Calculation A+B.
It should be noted that :A and B Each digit is given by the corresponding English word .

Input

The test input contains several test cases , One line per test case , The format is "A + B =", There is a space between two adjacent strings . When A and B Also for 0 When the input is over , Do not output the corresponding result .

Output

Output for each test case 1 That's ok , namely A+B Value .

Solve：

Basically, there are only two points ： English to number mapping and format control , Just look at the code

AC Code：

#include <iostream>
#include <map>
#include <cstring>
using namespace std;
map<string, int>mp;
int a, b;
string s;
int main(void)
{
	//map mapping  
	mp["one"] = 1;     mp["two"] = 2;
	mp["three"] = 3;   mp["four"] = 4;
	mp["five"] = 5;    mp["six"] = 6;
	mp["seven"] = 7;   mp["eight"] = 8;
	mp["nine"] = 9;    mp["zero"] = 0;	
	// Loop in  
	while(true)
	{
		a = b = 0;
		// The first number  
		while(cin >>s){
			if(s == "+") break;
			a = a * 10 + mp[s];
		}
		// The second number  
		while(cin >>s){
			if(s == "=") break;
			b = b * 10 + mp[s];
		}
		// Output  
		if(a == 0 && b == 0) break;
		cout <<a + b <<endl;
	}
	return 0;
}

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