[C language] nextday problem

 Enter a time , Bless The Child , Output the next day 
 Mainly boundary control , Don't use stupid writing , No technical content , Just a logical test 
 The notes are perfect , Self understanding 

 execution environment ：Ubuntu18.04  CLion/GCC		
					   WIndows The environment does not need to be modified 

Code：

/* Next Day *  Be careful ： Closely follow the topic , The input format is ：xx year xx month xx Japan , Just use this exercise to format strings sscanf() function  *  As for example 2019 02 25 This format , In this way , The writing is even more boring  *  Including unnecessary opening up space in the reactor area , At the same time, it also avoids the stack overflow problem caused by users' intentional unlimited input  *  Learning software testing , It is necessary to consider that nothing is wrong  *  Postgraduate students can learn more about these functions  * * */
#include <stdio.h>
#include <stdlib.h>

int main(void) {
    
    // Definition 13 Length ,0 No. index does not use , Avoid late +1 operation 
    int monArray[13] = {
    0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    printf(" Enter the date [Format：xx year xx month xx Japan ]：\n");

    // Open up space in the reactor area , Stack space Windows Only by default 1M,Linux General default 8M, It can be expanded , I won't go into details here 
    char *time = malloc(64);
    scanf("%s", time);

    int year, mon, day;

    // The format string is placed in the corresponding variable 
    sscanf(time, "%d year %d month %d Japan ", &year, &mon, &day);

    // Judge after leap year 2 Month array days plus one 
    if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
        monArray[2]++;

    // month , The day did not exceed the range 
    if ((mon <= 12 && mon >= 1) && (day <= monArray[mon])) {
    
        // End of month judgment 
        if (day == monArray[mon]) {
    
            // At the end of the year 
            if (mon == 12) {
    
                day = 1;
                mon = 1;
                year++;
            }
                // Only the end of the moon 
            else {
    
                day = 1;
                mon++;
            }
        }
            // Both month and day are out of range 
        else {
    
            day++;
        }
    }
        // Month day is out of range , direct return
    else {
    
        printf("Data Error\n");
        return EXIT_FAILURE;
    }

    // Calculation successful 
    printf("Next Day is:%d year %d month %d Japan \n", year, mon, day);
    return EXIT_SUCCESS;
}