Leetcode 48. Rotate image (yes, resolved)

Given a n × n Two dimensional matrix of matrix Represents an image . Please rotate the image clockwise 90 degree .

You must be there. In situ Rotated image , This means that you need to modify the input two-dimensional matrix directly . Please do not Use another matrix to rotate the image .

Example 1：

 Input ：matrix = [[1,2,3],[4,5,6],[7,8,9]]
 Output ：[[7,4,1],[8,5,2],[9,6,3]]

Example 2：

 Input ：matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
 Output ：[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]

Tips ：

• n == matrix.length == matrix[i].length
• 1 <= n <= 20
• -1000 <= matrix[i][j] <= 1000

Code:

class Solution {
    
public:
    void rotate(vector<vector<int>>& matrix) {
    
        vector<int>res;
        
        int size=matrix.size();
        for(int i=0;i<matrix.size();i++)
        {
    
            vector<int>sub=matrix[i];
            for(int j=0;j<sub.size();j++)
            {
    
                res.push_back(sub[j]);
            }
        }
        vector<int>newvec;
        
        for(int i=res.size()-size,row=0;i<res.size();i++,row++)
        {
    
            int j=i;
            int col=0;
            do
            {
    
                // cout<<res[j]<<" ";
                
                newvec.push_back(res[j]);
                matrix[row][col++]=res[j];
                j-=size;
                if(j>=0&&j<size)
                {
    
                    // cout<<res[j]<<" ";
                    newvec.push_back(res[j]);
                    matrix[row][col++]=res[j];
                    break;
                }
                if(j<0)
                {
    
                    break;
                }
            }while(1);
            cout<<endl;
        }
        
    }
};