Pointer variables -printf%d and%p meaning

1. The value of the pointer variable is the address , The address is usually 16 Hexadecimal said

2.int a=1;

int* p=&a;

printf("%d\n",p); and printf("%p\n",p); What's the difference , The output is p Value ,%p Pointer variable p Stored in the a The address of is output in hexadecimal ,%d Is that so? p Stored in the a The address of is output in decimal form . The output is p Value , Don't understand it as %p, It's a p The address output of .

%p It is specially used for pointer variables , Output the value stored in the pointer variable , That is, the address of other variables , It's just output in hexadecimal form .

So there's another problem , since %p All are hexadecimal , Then use %x Not line? ？

%p It is specially used for pointer variables , The output is the address in hexadecimal form .%x Is to output variables in hexadecimal form , When you want to see what address is stored in the pointer variable , Just use %p.

Let's use the program to see the running results ：

#include<stdio.h>

int main(void)
{
	int a = 1;
	int* p = &a;
	printf("%d\n", p);
	printf("%p\n", p);// This is the most correct , Pointer variables are collocated %p For the output 
	printf("%x\n", p);
	printf("\n");
	printf("%d\n", &a);
	printf("%x\n", &a);
	printf("%p\n", &a);// This is the most correct ,&a It's a pointer 


	return 0;
}

13630412
00CFFBCC//%p
cffbcc

13630412
cffbcc
00CFFBCC//%p
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