Check password

One 、 Title Description

This topic requires you to help the user registration module of a website write a small function of password legitimacy check . The website requires that the password set by users must be no less than 6 Characters make up , And can only have English letters 、 Numbers and decimal points  ., There must also be both letters and numbers .

Two 、 Input format

The first line of input gives a positive integer N（≤ 100）, And then N That's ok , Each line gives a password set by the user , For no more than 80 A non empty string of characters , End with a carriage return .

Be careful ：  The title guarantees that there is no input with only decimal point .

3、 ... and 、 Output format

Password for each user , Output system feedback information in one line , Below 5 Kind of ：

• If the password is legal , Output Your password is wan mei.;
• If the password is too short , Whether legal or not , All output Your password is tai duan le.;
• If the password length is legal , But there are illegal characters , The output Your password is tai luan le.;
• If the password length is legal , But only letters, no numbers , The output Your password needs shu zi.;
• If the password length is legal , But only numbers, no letters , The output Your password needs zi mu..

Four 、 sample input

5
123s
zheshi.wodepw
1234.5678
WanMei23333
pass*word.6

sample output

Your password is tai duan le.
Your password needs shu zi.
Your password needs zi mu.
Your password is wan mei.
Your password is tai luan le.

5、 ... and 、 Code demonstration  

#include<stdio.h>
#include<string.h>
int main()
{
    int n;
    scanf("%d", &n);// Output n
    getchar();
    char a[81];

    int len;
    while (n--)
    {
        int cha = 0, num = 0, point = 0, other = 0;
        gets(a);
        len = strlen(a);
        if (len < 6) {
            printf("Your password is tai duan le.\n");
            continue;
        }
        else for (int i = 0; i < len; i++)
        {
            if (a[i] >= '0' && a[i] <= '9')num++;
            else if (a[i] >= 'a' && a[i] <= 'z' || a[i] >= 'A' && a[i] <= 'Z')cha++;
            else if (a[i] == '.')point++;
            else other++;
        }
        if (other != 0)printf("Your password is tai luan le.\n");
        else if (cha != 0 && num == 0)printf("Your password needs shu zi.\n");
        else if (cha == 0 && num != 0)printf("Your password needs zi mu.\n");
        else printf("Your password is wan mei.\n");
    }
    return 0;
}