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js数组拼接的四种方法[通俗易懂]
2022-07-01 20:42:00 【全栈程序员站长】
大家好,又见面了,我是你们的朋友全栈君。
var a = [1,2,3,4,5,6];
var b=["foo","bar", "fun"];
最终的结果是:
[1,2,3,4,5,6,"foo","bar","fun"]
方法1:concat
c=a.concat(b);
c是新数组,此时内存使用有,c,a,b三个数组。
方法2:不使用新数组
for(var i=0;i<b.length;i++){
a.push(b[i]);
}
b=null;
没有新的数组创建,对于内存来说更优。注意到结尾的b=null;拼接完成后将数组b清空。
方法3:apply(推荐)
a.push.apply(a,b);
方法4:es6的写法(推荐)
a.push(...b);
发布者:全栈程序员栈长,转载请注明出处:https://javaforall.cn/130469.html原文链接:https://javaforall.cn
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