C language confession code?

Problem-solving ideas: I have divided this example into 4 parts, part of the first 3 lines, part of lines 4-6, part of lines 7-13, and part of the last line. Readers please read the notes carefully.Xiaolin wrote very detailed.

The first three lines of output, just to let beginners know that even the dumbest method can be printed.

Lines 4-6, these three lines have the same output effect.

for(i=0;i<3;i++){for(j=0;j<29;j++){printf("*");}printf("\n");}

Last line, just output a *.

for(i=0;i<14;i++){printf(" ");}printf("*\n");

Source code demo: Please refer to the above screenshots for the first three lines of code style. The source code spaces in the article are a little buggy:

#include//Header fileint main()//main function entry{printf("**** ****\n");//Print the first lineprintf(" ********* *********\n");//Print the second lineprintf("**************** *************\n");//Print the third lineint i,j;//Define variablesfor(i=0;i<3;i++)//Print 4-6 lines, a total of 3 lines, so i is less than 3{for(j=0;j<29;j++)//limit the number of output * per line{printf("*");//These three lines only print *, no spaces}printf("\n");//After printing a line, you need to wrap}for(i=0;i<7;i++) //Print 7-13 lines, a total of 7 lines, so i is less than 7{for(j=0;j<2*(i+1)-1;j++)//This for loop is parallel to the following for{printf(" ");//print spaces}for(j=0;j<27-i*4;j++)//The reader can bring in several numbers to find the conditions{printf("*");//print*}printf("\n");}for(i=0;i<14;i++)//Print the * of the last line{printf(" ");//print spaces}printf("*\n") ;//print*return 0;}

Compiling and running results are as follows:

The * in the above code can be replaced by the reader. The reader can try to replace it with this symbol to see if it is feasible, and think about it by yourself.

The second kind of confession source code demonstration:

#include//Header file#include//In order to refer to the pow functionint main()//main function entry{float y, x, z;//Define floating point variablesprintf("I think of you when I'm alone\n");//Prompt statementprintf("I want to hug you when I cry\n");//Prompt statementprintf("I want to pounce on you when I'm happy\n");//Prompt statementprintf("I want to kiss you when I'm excited\n");//Prompt statementprintf("Everything is done in the three-word signature without signing\n");//Prompt statementprintf("\n");//Newlinefor (double y = 2.5; y >= -1.6; y = y - 0.2){for (double x = -3; x <= 4.8; x = x + 0.1){//The following is a ternary operation, please read carefully, || this is or(pow((x*x + y*y - 1), 3) <= 3.6*x*x*y*y*y|| (x>-2.4 && x<-2.1 && y<1.5 && y>-1)|| (((x<2.5 && x>2.2) || (x>3.4 && x<3.7)) && y>-1 && y<1.5)|| (y>-1 && y<-0.6 && x<3.7 && x>2.2)) ? printf("*") : printf(" ");}printf("\n");//Newline}getchar();return 0;//The return value of the function is 0}

The results of compilation and running are as follows:

There are many ways to print a heart shape in C language. Readers can try more by themselves. Even using printf line by line is also a way. I can only help you here. My girlfriend still has to find it by herself./p>

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