Electronic Association C language level 1 33, odd even number judgment

Electronics Association C Language 1 level  33 、 Odd even judgment

OpenJudge - 03: Odd even judgment

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C＋＋ Code ： Method 1

/*
 Electronics Association  C Language  1 level   33 、 Odd even judgment   Method 1  
http://noi.openjudge.cn/ch0104/03/

 Given an integer , Judge whether the number is odd or even .
 Input 
 Enter only one line , A positive integer greater than zero  n.
 Output 
 Output only one line , If  n  Is odd , Output  odd; If  n  It's even , Output  even.
 The sample input 
5
 Sample output 
odd
*/
#include<iostream>
using namespace std;
int main()
{
	int n;
	cin>>n;
	
	( n%2 == 0 ) ? cout<<"even" : cout<<"odd" ;  
	
	//cout<<int(3.5); 
	
	return 0;
}

---

C++ Code ： Method 2

/*
 Electronics Association  C Language  1 level   33 、 Odd even judgment   Method 2  
http://noi.openjudge.cn/ch0104/03/

 Given an integer , Judge whether the number is odd or even .
 Input 
 Enter only one line , A positive integer greater than zero  n.
 Output 
 Output only one line , If  n  Is odd , Output  odd; If  n  It's even , Output  even.
 The sample input 
5
 Sample output 
odd
*/
#include<iostream>
using namespace std;
int main(void)
{                                                                                                                                                                     
	int x; 
	cin>>x;
	
	if( x%2==1)
	{
		cout<<"odd"<<endl;
	}
	else
	{
		cout<<"even"<<endl;
	}
	return 0;
}

---

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C Code ：

#include <stdio.h>
#include <stdlib.h>
int main()
{
	int a;
	
    scanf("%d",&a);
    
	if(a%2==0)  printf("even");
    else        printf("odd");
    
	//system("pause");
	
	return 0;
}

---

---

python3 Code ：

n = int(input())

if n % 2:
    print("odd")
else:
    print("even")

---

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