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电子协会 C语言 1级 33 、奇偶数判断
2022-07-02 01:29:00 【dllglvzhenfeng】
电子协会 C语言 1级 33 、奇偶数判断
C++代码:方法一
/*
电子协会 C语言 1级 33 、奇偶数判断 方法一
http://noi.openjudge.cn/ch0104/03/
给定一个整数,判断该数是奇数还是偶数。
输入
输入仅一行,一个大于零的正整数 n。
输出
输出仅一行,如果 n 是奇数,输出 odd;如果 n 是偶数,输出 even。
样例输入
5
样例输出
odd
*/
#include<iostream>
using namespace std;
int main()
{
int n;
cin>>n;
( n%2 == 0 ) ? cout<<"even" : cout<<"odd" ;
//cout<<int(3.5);
return 0;
}C++代码:方法二
/*
电子协会 C语言 1级 33 、奇偶数判断 方法二
http://noi.openjudge.cn/ch0104/03/
给定一个整数,判断该数是奇数还是偶数。
输入
输入仅一行,一个大于零的正整数 n。
输出
输出仅一行,如果 n 是奇数,输出 odd;如果 n 是偶数,输出 even。
样例输入
5
样例输出
odd
*/
#include<iostream>
using namespace std;
int main(void)
{
int x;
cin>>x;
if( x%2==1)
{
cout<<"odd"<<endl;
}
else
{
cout<<"even"<<endl;
}
return 0;
}C代码:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int a;
scanf("%d",&a);
if(a%2==0) printf("even");
else printf("odd");
//system("pause");
return 0;
}python3代码:
n = int(input())
if n % 2:
print("odd")
else:
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