Shell script echo command escape character

echo It's a Shell Built in command , Used to output a string at the terminal , and Add line break at the end by default .

Output does not wrap

echo After the command is output, the default line will wrap , If you don't want a new line , You can add -n Parameters , As shown below ：

#!/bin/bash
name="Tom"
age=20
height=175
weight=62
echo -n "${name} is ${age} years old, "
echo -n "${height}cm in height "
echo "and ${weight}kg in weight."
echo "Thank you!"

Output ：

Tom is 20 years old, 175cm in height and 62kg in weight.
Thank you!

Output escape characters

By default ,echo Will not parse with backslash \ The escape character at the beginning . such as ,\n Means line break ,echo It will be treated as a normal character by default . Please see the following example ：

[[email protected] ~]# echo "hello \nworld"
hello \nworld

Parameters ：-e

We can add -e Parameters to make echo Command parses escape characters

[[email protected] ~]# echo -e "hello \nworld"
hello
world

Escape character ：\c

With -e Parameters , We can also use escape characters \c Mandatory echo The command doesn't wrap

#!/bin/bash
name="Tom"
age=20
height=175
weight=62
echo -e "${name} is ${age} years old, \c"
echo -e "${height}cm in height \c"
echo "and ${weight}kg in weight."
echo "Thank you!"

Output ：

Tom is 20 years old, 175cm in height and 62kg in weight.
Thank you!