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20. Valid Parentheses

2022-08-03 15:59:00 【51CTO】

Given a string containing just the characters’(’,’)’,’{’,’}’,’[‘and’]’, determine if the input string is valid.
The brackets must close in the correct order,"()“and”()[]{}“are all valid but”(]“and”([)]"are not.

       
       import java.util.Stack;
       
public class Solution {
       
    public boolean isValid(String s) {
       
        Stack<Character> stack = new Stack<Character>();
       
        //使用foreach循环
       
        for (char c : s.toCharArray()) {
       
            if (c == '(')
       
                stack.push(')');
       
            else if (c == '{')
       
                stack.push('}');
       
            else if (c == '[')
       
                stack.push(']');
       
            else if (stack.isEmpty() || stack.pop() != c)
       
                return false;
       
        }
       
        return stack.isEmpty();
       
    }
       
}
      
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Java2

       
       class Solution {
       
    public boolean isValid(String s) {
       
        Stack<Character> stack = new Stack<>();
       
        for (char c : s.toCharArray()) {
       
            if (c == '(' || c == '[' || c == '{')
       
                stack.push(c);
       
            else {
       
                if (stack.isEmpty())
       
                    return false;
       
                if (c == ')') {
       
                    if ('(' != stack.pop())
       
                        return false;
       
                } else if (c == ']') {
       
                    if ('[' != stack.pop())
       
                        return false;
       
                } else if (c == '}') {
       
                    if ('{' != stack.pop())
       
                        return false;
       
                }
       
            }
       
        }
       
        return stack.isEmpty();
       
    }
       
}
      
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版权声明
本文为[51CTO]所创，转载请带上原文链接，感谢
https://blog.51cto.com/u_15740726/5540545

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20. Valid Parentheses

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