[LeetCode] 反转字符串中的单词 III【557】

问题: 给定一个字符串s，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序

示例1

输入: s = "Let's take LeetCode contest"

输出: "s'teL ekat edoCteeL tsetnoc"

示例2

输入: s = "God Ding"

输出: "doG gniD"

Python3解题

# 解法1
def reverseWords(s):
    res = []
    arrs = s.split(" ")
    for val in arrs:
        new_val = val[::-1]
        res.append(new_val)
    last_res = ' '.join(res)
    return last_res

reverseWords("Let's take LeetCode contest")
reverseWords("God Ding")

涉及知识点:

[Python] join()方法https://blog.csdn.net/Hudas/article/details/122850092[Python] split()方法https://blog.csdn.net/Hudas/article/details/122849811