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[learning notes] segment tree selection
2022-07-07 13:09:00 【Ants looking up at the starry sky】
It's all violence
It's tiring to hit the line tree
Fibonotci
At first glance, this linear recurrence relationship is obviously matrix multiplication
The code ...
call .. Finished writing .
Two Permutations
Sequence hash ?
Rather, it is called segment tree maintenance sequence hash Worth a good question
analogy Permutation . The essence is to express complex states as an integer , This complexity is better .
Strange Addition
Obviously, segment tree maintenance dp .
Attention to detail . And don't be too heavy .
If the implementation is fine, you don't need to go to the leading zero . Slight seizure .
Strange Array
Worship wicton .
This question is not so obvious .
Consider from [i,i] Expand
Discussion on parity between partitions
Consider one < a i <a_i <ai The sum of > a i >a_i >ai The number of will offset
hold a i a_i ai as < a i <a_i <ai and > a i >a_i >ai Consider two cases twice , In this way, equal elements will not appear
take ≤ a i \leq a_i ≤ai The number of 1 1 1 , > a i >a_i >ai The number of − 1 -1 −1
Expand left and right respectively , Find the largest sub segment and a n s ans ans , Contribution: ⌊ a n s − 1 2 ⌋ \lfloor\frac{ans-1}{2}\rfloor ⌊2ans−1⌋
take ≥ a i \geq a_i ≥ai The number of 1 1 1 , < a i <a_i <ai The number of − 1 -1 −1
Expand left and right respectively , Find the largest sub segment and a n s ans ans , Contribution: ⌊ a n s 2 ⌋ \lfloor\frac{ans}{2}\rfloor ⌊2ans⌋
The code ...
call .. Finished writing .
Phoenix and Memory
He who travels a hundred miles , Half 90 .
First, greedy for a group of solutions
If you want to get different sequences , There must be ( i , j ) (i,j) (i,j) ( i ≠ j ) (i\ne j) (i=j) bring l i ≤ a j ≤ r i l_i\leq a_j\leq r_i li≤aj≤ri also l j ≤ a i ≤ r j l_j\leq a_i\leq r_j lj≤ai≤rj
Perceptual understanding , If you change more on the greedy optimal plan , The plan is even worse .
Proof omitted .
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