1082 read number in Chinese (25 points)

1082 Read Number in Chinese (25 branch )

The question

Give an integer , It is required to output its Chinese pronunciation .
Such as “-123456789” pronounce as “Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu”
“100800” pronounce as “yi Shi Wan ling ba Bai”

Ideas

simulation , Because the number of digits is very small , It can be solved directly . Divide the numbers into three groups
A bit to a thousand | Tens of thousands to tens of millions | Billion
It can be read as a single digit to a thousand digit . Determine the relative position of each group , The first set of direct outputs , Add ten thousand at the end of the second group , Add a hundred million to the third group .
Note the ‘0’, Zeros at the end of a group are not read , Connected zeros read only one . Be careful 0 The number of , Note blank space .

Code

#include<stdio.h>
#include<string.h>

char figure[12][10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
char weight[12][10]={"","Shi","Bai","Qian","Wan","Yi"};
int main()
{
	char number[20];
	int len,star=0,flag=0;
	scanf("%s",number);
	len=strlen(number);
	if(len==1&&number[0]=='0'){
		printf("ling");
	}else{
		if(number[0]=='-'){
			printf("Fu ");
			star=1;
			len-=1;
		}
		for(int i=star;i<star+len;i++){
			if(i!=star&&number[i]!='0'){
				printf(" ");
			}
			if(number[i]!='0'){
				if(flag!=0){
					printf("ling ");
					flag=0;
				}
				printf("%s",figure[number[i]-'0']);
				flag=0;
				if((star+len-i-1)%4!=0){
					printf(" %s",weight[(star+len-i-1)%4]);
				}
			}else{
				if(flag==0){
	//				printf("ling");
					flag++;
				}
			}
			if((star+len-i)%4==1&&star+len-i>4){
				printf(" %s",weight[(star+len-i)/4+3]);
				flag=0;
			}
		}
	}
	return 0;
}