Static LED display developed by single chip microcomputer

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 一、题目

静态LED显示

二、要求

1、画出流程图

2、编写源程序并进行注释

3、记录实验过程

4、记录程序运行结果截图

三、过程及结果记录

按照思路搭建电路图1如下：

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图1：实验电路图

7SEG2 Displays nixie tubes for ten digits,7SEG1 Display the digital tube for the one digit,KEY_LOAD:Countdown initial value button,KEY_START：Countdown start button

功能：KEY_LOAD按钮被按下时,Load the initial countdown value（10S）;当按下KEY_START按钮时,开始倒计时,每过1S,计数器减1,直到见到“00”为止.减到“00”时,使P3.0引脚上的LED按10HzThe frequency flashes,直到再次按下KEY_LOAD按钮,Just reload the initial value,并熄灭LED;再次按下KEY_STARTThe button starts the countdown again,如此反复

1. 使用Proteus搭建实验电路图如上,并将其保存为staticLED_self.DSN 文件.

2. Write the control source program,将其保存为staticLED_self.asm.

3. 程序编译：单击上方工具栏的source,然后build all,将asm文件编译成hex文件.将可执行文件hex写入芯片

4. Execute the simulation process to observe whether the stopwatch program functions correctly.实验结果如下图所示：

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图2：Load the initial value and start

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图3：减到00,LED灯闪烁

四、流程

The experimental flow chart is shown below:

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图4：实验流程图

1.Determine what the addresses of the two latches are0FE00H和0FD00HAnd add two display nixie tubes.按照要求将P1.0作为start的输入,P1.1作为load的输入.

2.实验开始,判断P1.1Whether the mouth is pressed,load the initial value,And let the two digital tubes display the initial value.

3.判断P1.0是否按下,Counting starts when pressed;If not pressed,returns to the initial state,等待P1.1按下.

4.计数完成后,Waiting for the load command,若无,then stay and wait,若有,Start the next cycle.

5.The control command to display the nixie tube can be written first,存在内存中,Then use relative addressing to perform data access to this continuous address,assigned to the latch.Write the control signal of the digital tube in the memory,并且按照1到9的顺序存放.Use two memory cells to store tens and ones digits,This number also corresponds to the offset in the control signal table.即数字为n的时候,偏移n进行查表,将nThe representative control signal is given to the digital tube.

6.Begin to judge the set operation first,调用初始化10的指令.Set the ones digit0,Tens place1,Then his offsets in the table are respectively0和1,使用movcThe command looks up the table to get the corresponding control signal,to the latch,That is digital tube.然后判断start信号,If so, start counting,If not, skip back to the beginning,Waiting for new instructions.当有start信号,Then call the display program,digital display.

7.Call the adjuster count.Put the number in the one digit,即30HThe corresponding number in the memory unit is subtracted1,然后和-1比较,要是不等于-1,That means the original one has not arrived yet0,Do not operate on tens.若是为-1,Indicates that the original position has arrived0,Then subtract ten1,and a location9.Compare ten,若是为-1,说明原来是0,Then it indicates that the counter has arrived00,计数结束.

8.After performing the adjustment,Do not change the display yet,Instead, the delay program is called to wait for a period of time,Refreshing the display of the nixie tube.

五、源代码

ORG 0000H			; 在内存的0地址处就强制转到主程序上去,绕过中断程序 AJMP MAIN    ; 无条件的转移到主程序ORG 0030H     MAIN:				   ;定义主程序   MOV  SP,#60H		  ;设置栈指针   CLR F0			 ; 使用CLR位操作指令将PSW.6User flags are cleared   SETB P3.0		  ;设置LED端口,使LED灭   LCALL INITIALIZE0  ; 调用子程序,显示为00LOOP:    ; 定义循环       JB P1.1,GOON    ; 位操作指令,判断P1.1口值,若为0,则说明KEY_LOAD按键按下,继续执行下面的程序,Otherwise, jump to is not pressedGOON ,判断是否有start命令WAIT0: LCALL INITIALIZE    ;The initial value is displayed10       CLR F0			;Set the user flag bit to zeroGOON: JB P1.0,LOOP		; 判断P1.0口值,若为0,则说明KEY_START按下,开始计时,Otherwise, jump back to start re-judgmentP1.1NEXT1:     	  LCALL DISPLAY	   ; 调用子程序DISPLAY	  LCALL DELAY1S	   ; 调用子程序DELAY1S	  LCALL ADJUST	   ; Call the adjustment subroutineADJUST	  JB F0,SHINING	   ;If the timer register is 0,The subroutine is calledSHINING,使其闪烁	  LJMP NEXT1	   ; when the counter is not zero,则继续循环	  SHINING:			        CLR P3.0			;将P3.0置零,点亮LED灯		LCALL DELAY50MS		; 调用延时50MS子程序		SETB P3.0		    ;  将P3.0置1,此时LED灭		LCALL DELAY50MS		; 调用延时50ms子程序		JB P1.1,SHINING		; 判断KEY_LOAD是否按下		SJMP WAIT0      ; 若按下,then jump back to the beginningDELAY50MS:					 ; 定义延时50MS子程序         MOV R6,#100   ; 外层循环为100次	 DL: MOV R5,#250     ; 内层循环为250次	      DJNZ R5,$     ;两个时钟周期		  DJNZ R6,DL     ; 两个时钟周期    RET ;The total delay can be calculated（1μs*2*250+2+1）*100+1=50.30ms     DELAY1S:MOV R7,#10		  ;延时1S子程序    DL2:MOV R6,#200     ; 第二层循环200次	DL1:MOV R5,#250    ; 第三层循环250次	   DJNZ R5,$      ;两个时钟周期	   DJNZ R6,DL1   ; 两个时钟周期	   DJNZ R7,DL2    ; 两个时钟周期       RET   ;The total delay can be calculated（（1μs*2*250+1+2）*200++2+1）*10+1=1s  ADJUST:		   DEC 30H	; One digit minus one   MOV A,30H			 ; Compare units,If the unit is not-1,则返回   CJNE A,#-1,GOTORET  ;If the unit is -1（原来为0）,则置9   MOV 30H,#9    ; Direct addressing operation,直接赋值9   DEC 31H				 ; 十位减一   MOV A,31H        CJNE A,#-1,GOTORET	 ;  If ten is not-1,则返回   SETB F0				 ;If ten is-1,则说明为00,That is, counting ends.Set the timer register1   RET	GOTORET:RETINITIALIZE0:			       MOV 30H,#0  ;初始化		MOV 31H,#0    		CLR A  		MOV DPTR,#TABLE   ;Give the address of the formDPTR		MOVC A,@A+DPTR    ;访问片外ROM,所以用movc		MOV DPTR,#0FE00H    ;使DPTRPoint to the latch		MOVX @DPTR,A    ;Assign a value to the latch		MOV A,#0     ; 清空		MOV DPTR,#TABLE    ;Assign value to memory0		MOVC A,@A+DPTR   ;Pay data toA寄存器		MOV DPTR,#0FD00H   ;Assign a value to the latch		MOVX @DPTR,A    ;Pay the number to the memory unit		RET INITIALIZE:		 ;Initialization is shown as10子程序        MOV 30H,#0         ;give the memory address30清零		MOV 31H,#1     ;give the memory address31H置1		CLR A		MOV DPTR,#TABLE		MOVC A,@A+DPTR		MOV DPTR,#0FE00H		MOVX @DPTR,A    ;Send the control signal to the latch		MOV A,#1     ; 偏移地址加1,Control the display of the second nixie tube1		MOV DPTR,#TABLE		MOVC A,@A+DPTR		MOV DPTR,#0FD00H		MOVX @DPTR,A		RETDISPLAY:				  ;Refresh the subroutine        MOV A,30H     		MOV DPTR,#TABLE   ; 让DPTRPoint to the first address of the form		MOVC A,@A+DPTR    ; 读取第一个数字		MOV DPTR,#0FE00H    ; This control signal is sent to the latch		MOVX @DPTR,A   		 MOV A,31H  		MOV DPTR,#TABLE  		MOVC A,@A+DPTR    		MOV DPTR,#0FD00H ; The read control signal is sent to the latch		MOVX @DPTR,A   		RETTABLE: DB 0C0H,0F9H,0A4H,0B0H,99H,92H,82H,0F8H,80H,90H  ; 定义表格,END     

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