mysql delete execution error: You can't specify target table 'doctor_info' for update in FROM clause

for some testing reasons,This led to the appearance of two doctors in the doctor tableID相同的数据,也就是所谓的脏数据,So how to delete the redundant one？

一、First filter out the number of bars greater than1条的：

select doctor_id,count(doctor_id) from `doctor_info` where `scale_group_id`="31" group by doctor_id having count(doctor_id)>1

二、Decided to delete that one？max/min

1、max

select max(id) as id from doctor_group_permission where `scale_group_id`="24120868141551631" group by doctor_id  having count(doctor_id)>1

2、min

select min(id) as id from doctor_group_permission where `scale_group_id`="24120868141551631" group by doctor_id  having count(doctor_id)>1

三、The data is filtered out,直接delete 报错了

 delete from doctor_info where id in(select max(id) as id from doctor_info where `scale_group_id`="31" group by doctor_id  having count(doctor_id)>1)

四、错误说明

不能先select出同一表中的某些值,再update这个表(在同一语句中),即不能依据某字段值做判断再来更新某字段的值.
Borrow a temporary table to deal with it,Front-end time wrote oneupdate的,链接在此

五、正确delete操作 借用临时表a

delete from doctor_info where id in(select a.id from(select max(id) as id from doctor_info where `scale_group_id`="31" group by doctor_id  having count(doctor_id)>1) a)