Written test question "arrange version numbers from large to small"

Arrange the version numbers from large to small

for example [‘1.2.3’,‘2.2.1’,‘10.1.0’,‘9.99.9’,‘10.1.0’]
Output [‘1.2.3’,‘2.2.1’,‘9.99.9’,‘10.1.0’,‘10.1.0’]

Ideas

How to compare version numbers ？
Version number x.y.z, Compare first x, If x equal , Compare again y, If y Also equal , Last comparison z.
My idea is to change each element from a string to a string “.” Split array , Form a two-dimensional array , Using built-in functions sort To compare .

Code

//  Arrange the version numbers from large to small 
//  for example  ['1.2.3','2.2.1','10.1.0','9.99.9','10.1.0']
//  Output  ['1.2.3','2.2.1','9.99.9','10.1.0','10.1.0']
function sortVersion(array) {
    
  for (let i = 0; i < array.length; i++) {
    
    array[i] = array[i].split('.')
  }
  array.sort((a, b) => {
    
    return a[0] - b[0] || a[1] - b[1] || a[2] - b[2] //  Compare the version numbers first x, If x Equal recomparison y, If x,y All equal final comparison z.
  })
  for (let i = 0; i < array.length; i++) {
    
    array[i] = array[i].join()
  }
  console.log(array)
}
sortVersion(['1.2.3', '2.2.1', '10.1.0', '9.99.9', '10.1.0'])
sortVersion([
  '1.2.3',
  '2.2.1',
  '10.1.0',
  '9.99.9',
  '10.1.0',
  '3.14.15',
  '3.15.12',
  '3.14.16',
])