JS - max. of array cases

One 、 subject

 Find an array [2,6,1,77,52,25,7] The maximum 

Two 、 Source code

      <script>
      //  Find an array [2,6,1,77,52,25,7] The maximum 
      var arr = [2, 6, 1, 77, 52, 25, 7];
      var big = 0;
      for (var i = 1; i < arr.length; i++) {
        if (arr[big] > arr[i]) {
        } else {
          arr[big] = arr[i];//  Extract the one that is larger than the last digit 
        }
      }
      console.log(arr[big]);/* Output 77*/
    </script>

3、 ... and 、 Ideas

The index number that declares a maximum value . Compare the maximum value with the array elements in turn , Choose which is the largest value .

• The index number that declares a maximum value 0,, Is to select the first element to match .
• Since the maximum index value and the first array element are obtained here 2, It should be 2 And the next array element 6 To compare , therefore i It should start from the second of the array , Namely i=1
• When i=1,2 And 6 Match ,6 Bigger , That is, the index number is 1 It's bigger , Assign a larger element to arr[big], such 6 It is extracted and compared with the following values .
• If the following value is greater than 6 Big , Then the value is updated to the maximum value , If less than 6, Do nothing , The maximum is still 6.