Calculate S=a+aa+…+aa…a

0 Introduction

Using python to write code can be used to easily solve mathematical operation problems.

1 Question

Find the value of s= a + aa + aaa + … + aa…a (the number of a in the last number is n), where a is a number from 1 to 9, for example: 2 + 22 + 222 +2222 + 22222.

Input: One line, including two integers, the first is a, the second is n (1 ≤ a ≤ 9, 1 ≤ n ≤ 9), separated by commas.

Output: one line, the value of s.

2 Method

Define a function that uses a for loop to continuously add up, and reassign the original input value a to obtain the calculation of the sum of a+aa+aaa+…+a…a.The input a and n should be separated by commas and use the split function.

3 Experimental Results and Discussion

It has been proved through experiments and practice that the proposed method is effective and can solve the problems raised at the beginning.

Code Listing 1

def get(a,n): Sn=0 sum=0 for i in range(1,n+1): Sn=Sn*10+a Sum+=Sn return sum a,n=map(eval,input('Please input a and n:').split(',')) result=get(a,n) print(result)

4 Concluding Remarks

In this question, functions and loop statements are used to calculate mathematical problems through programs, which makes the calculation convenient and fast, and can solve problems with large and many values.