175. Combine two tables (very simple)

Problem description ：

surface : Person

+-------------+---------+
| Name          | type      |
+-------------+---------+
| PersonId    | int     |
| FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
personId Is the primary key column of the table .
This table contains some people's ID And their last and first names .

surface : Address

+-------------+---------+
| Name          | type     |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
addressId Is the primary key column of the table .
Each row of the table contains a ID = PersonId Information about people's cities and states .

Write a SQL Query to report Person The last name of each person in the list 、 name 、 Cities and states . If personId Your address is not in Address In the table , The report is empty   null .

With In any order Return result table .

The query result format is as follows .

Example ：

Example 1:

Input :
Person surface :
+----------+----------+-----------+
| personId | lastName | firstName |
+----------+----------+-----------+
| 1        | Wang     | Allen     |
| 2        | Alice    | Bob       |
+----------+----------+-----------+
Address surface :
+-----------+----------+---------------+------------+
| addressId | personId | city          | state      |
+-----------+----------+---------------+------------+
| 1         | 2        | New York City | New York   |
| 2         | 3        | Leetcode      | California |
+-----------+----------+---------------+------------+
Output :
+-----------+----------+---------------+----------+
| firstName | lastName | city          | state    |
+-----------+----------+---------------+----------+
| Allen     | Wang     | Null          | Null     |
| Bob       | Alice    | New York City | New York |
+-----------+----------+---------------+----------+
explain :
There is no personId = 1 The address of , So their cities and States return null.
addressId = 1 Contains personId = 2 Address information for .

Pass times 403,646
Submit the number 547,216

On sql, Take it to run ：

CREATE TABLE `address` (
  `AddressId` int(10) NOT NULL AUTO_INCREMENT,
  `PersonId` int(10) DEFAULT NULL,
  `City` varchar(255) DEFAULT NULL,
  `State` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`AddressId`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;





CREATE TABLE `person` (
  `PersonId` int(11) NOT NULL AUTO_INCREMENT,
  `FirstName` varchar(255) DEFAULT NULL,
  `LastName` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`PersonId`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;

SELECT p.FirstName,p.LastName,a.City,a.State from  person as p  left join address as a  on a.PersonId=p.PersonId

I want to brush it 300 Algorithm questions , The first 108 Avenue