Symbol of array element product of leetcode simple problem

subject

Known functions signFunc(x) Will be based on x The positive and negative of returns a specific value ：
If x Positive number , return 1 .
If x It's a negative number , return -1 .
If x Is equal to 0 , return 0 .
Give you an array of integers nums . Make product Is an array nums The product of the values of all elements in .
return signFunc(product) .
Example 1：
Input ：nums = [-1,-2,-3,-4,3,2,1]
Output ：1
explain ： The product of all the values in the array is 144 , And signFunc(144) = 1
Example 2：
Input ：nums = [1,5,0,2,-3]
Output ：0
explain ： The product of all the values in the array is 0 , And signFunc(0) = 0
Example 3：
Input ：nums = [-1,1,-1,1,-1]
Output ：-1
explain ： The product of all the values in the array is -1 , And signFunc(-1) = -1
Tips ：
1 <= nums.length <= 1000
-100 <= nums[i] <= 100
source ： Power button （LeetCode）

Their thinking

   You only need to count the number of negative numbers to traverse the array , If the number of negative numbers is odd and there is no 0, So that is -1, If the number of negative numbers is even and there is no 0, So that is 1, If... Exists in the array 0, So that is 0.

class Solution:
    def arraySign(self, nums: List[int]) -> int:
        count=0
        for i in nums:
            if i<0:
                count+=1
            elif i==0:
                return 0
        return -1 if count%2 else 1