Is the array name the address of the first element?

The array name is indeed the address of the first element , But there are two exceptions .
1.sizeof（ Array name ）, The array name here is not the first element address , Represents the entire array .
Code up ：

int arr[10] = {
     0 };
	printf("%d\n", sizeof(arr));

The result is ：

If it is the address of the first element , stay 32 The size of the bit platform address is 4 Bytes ,64 The bit platform address size is 8 Bytes , But the output here is 40 byte , therefore sizeof（ Array name ） This situation , The array name represents the entire array .
2.& Array name , The array name here also represents the whole array .
Code up ：

int arr[10] = {
     0 };
	printf("%p\n", &arr);
	printf("%p\n", &arr[0]);
	printf("%p\n", &arr[0]+1);
	printf("%p\n", &arr+1);

The result is ：

&arr[0] and &arr[0]+1 Each represents an array arr The address of the first element and the address of the first element , The difference is 4, It's exactly the size of a plastic , We'll see &arr and &arr+1 The difference is 40,, Is precisely 10 The size of a plastic , therefore &arr Medium arr Represents the entire array .