DeprecationWarning: . ix is deprecated. Please use. loc for label based indexing or. iloc for positi

Copy the example Self experience

import pandas as pd
data = [[1,2,3],[4,5,6],[7,8,9]]
rows = ['row1','row2','row3']# Row labels 
columns = ['col1','col2','col3']# Column labels 
df = pd.DataFrame(data, index=rows, columns=columns)
print df

    col1  col2  col3
row1     1     2     3
row2     4     5     6
row3     7     8     9

print df.loc['row1']

col1    1
col2    2
col3    3
Name: row1, dtype: int64

print df.iloc[0]

col1    1
col2    2
col3    3
Name: row1, dtype: int64

print df.ix[0] print df.ix['row1']

col1    1
col2    2
col3    3
Name: row1, dtype: int64

It shows that the above three are equivalent ,

however loc and iloc More specifically , If you don't pay attention to it, you will make grammatical mistakes

ix More general , Estimation is prone to error

print df.ix['row1',‘col1’]   print df.ix['row1',0]

These two are specific to row number and column number , Direct positioning