Leetcode simple question check whether all characters appear the same number of times

subject

Give you a string s , If s It's a good character string , Please return true , Otherwise, please return to false .
If s In the all Number of occurrences of characters identical , So we call strings s yes good character string .
Example 1：
Input ：s = “abacbc”
Output ：true
explain ：s The characters that have appeared in are ‘a’,‘b’ and ‘c’ .s All characters appear in 2 Time .
Example 2：
Input ：s = “aaabb”
Output ：false
explain ：s The characters that have appeared in are ‘a’ and ‘b’ .
‘a’ There is 3 Time ,‘b’ There is 2 Time , The two appear different times .
Tips ：
1 <= s.length <= 1000
s Only lowercase letters .
source ： Power button （LeetCode）

Their thinking

   Count the frequency of each character in the string , Then randomly take the frequency of a character as the most contrast , Traverse the frequency table and compare whether the frequencies are consistent .

class Solution:
    def areOccurrencesEqual(self, s: str) -> bool:
        s=Counter(s)
        target=s.popitem()[1]
        for i in s.values():
            if i!=target:
                return False
        return True