LCP 17. Quick Calculation Robot

LCP 17. Quick Calculation Robot

Xiaokou found a quick calculation robot at the autumn market.The store owner says two numbers (denoted as x and y) to the robot, please give the calculation instruction:

"A" operation: make x = 2 * x + y;"B" operation: make y = 2 * y + x.

In this game, the numbers spoken by the store owner are x = 1 and y = 0, and the calculation instructions spoken by Xiaokou are recorded as a string s consisting of capital letters A and B only.order indicates the calculation order, please return what the final sum of x and y is.

Example 1:

input: s = "AB"output: 4explain:After one A operation, x = 2, y = 0.After another B operation, x = 2, y = 2.The final sum of x and y is 4.

This problem is actually very simple. The code to solve the problem is as follows:

int fA(int x,int y){return 2*x+y;}int fB(int x,int y){return 2*y+x;}int calculate(char* s){int i;int x=1,y=0;for(i=0;s[i]!='\0';i++){if(s[i]='A')span>{x=fA(x,y);}else{y=fB(x,y);}}return x+y;}