[daily question] - Huawei machine test 01

【 A daily topic 】— Huawei machine test 01

subject ：HJ1 The length of the last word in the string

describe

Calculate the length of the last word in the string , Words are separated by spaces , String length is less than 5000.（ notes ： The end of the string does not end with a space ）

Input description ：

The input line , Represents the string to be evaluated , Non empty , The length is less than 5000.

Output description ：

Output an integer , Represents the length of the last word of the input string .

Example 1

Input ：

hello nowcoder

Copy

Output ：

8

Copy

explain ：

 The last word is nowcoder, The length is 8   

Ideas ：

1. Use gets Enter a string

​ When reading a string ：
​ scanf() With Space、Enter、Tab End one input
​ gets() With Enter End input （ The space does not end ）, Accept spaces , Will abandon the last carriage return ！

2. Count from back to front , Until I met Space end .

️ The code is as follows

# define _CRT_SECURE_NO_WARNINGS 1
// Calculate the length of the last word in the string , Words are separated by spaces , String length is less than 5000.（ notes ： The end of the string does not end with a space ）
#include <stdio.h>
#include <assert.h>
int the_length_of_last_word(char* str, int i)
{
    
    int length = 0;
    assert(str);
    for (; i >= 0; i--)
    {
    
        if (str[i] == ' ')
        {
    
            break;
        }
        length++;

    }
    return length;
}
int main()
{
    
    char a[5000] = {
     0 };
    gets(a);
    int b = strlen(a) - 1;
    int lengh = the_length_of_last_word(a, b);
    printf("%d", lengh);
    return 0;
}

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