(pointer) write function void fun (int x, int *pp, int *n)

function ： Find out x Even factor of , And put them in the order from small to large pp In the array referred to , The number of these factors is determined by formal parameters n return ( hypothesis pp Point to enough space ).
Such as ：x by 24
Then six numbers meet the requirements ,2、4、6、8、12、24 All saved to pp in n by p
Code:

void fun(int x,int *pp,int *n)
{
    
    *pp=0;
    *n=0;
    int cnt=0;
    for(int i=2;i<=x;i++)
    {
    
        if(x%i==0)
        {
    
            if(i%2==0)
            {
    
                if(*pp==0)
                {
    
                    pp[cnt++]=i;
                    (*n)++;
                }
                else if(i>pp[--cnt])
                {
    

                    cnt++;
                    pp[cnt++]=i;
                    (*n)++;
                }
            }
        }
    }
}
int main()
{
    
	int aaa[100]={
    0};
    int ss=0;
    fun(512,aaa,&ss);
    for(int i=0;i<ss;i++)
    {
    
        cout<<aaa[i]<<endl;
    }
    return 0;
}