Blue Bridge Cup microbial proliferation C language

Microbial proliferation

Suppose there are two microorganisms X and Y

X Every... After birth 3 Split once a minute （ Double the number ）,Y Every... After birth 2 Split once a minute （ Double the number ）.

A new born X, Eat it in half a minute 1 individual Y, also , From the start , every other 1 Minutes to eat 1 individual Y.

It is now known that there are new born X=10, Y=89, seek 60 Minutes later Y Number of .

If X=10,Y=90 Well ？

The requirement of this question is to write under these two initial conditions ,60 Minutes later Y Number of .

The following program realizes this function , Please fill in the blanks ：

  Tips ：Y The separation will be in 0.5,1.5,2.5······ Be eaten when , therefore , hold 60 Minutes are divided into 120 Share , Then divide by 2 Remainder is 1 when ,Y The number of students is decreasing X individual

When X=10, Y=89, Code ：

#include<stdio.h>
int main()
{
	int x=10,y=89;
	for(int t=1;t<=120;t++)   // Half a minute is a unit  60 Minutes for 120 A unit of  
	{
		if(t%2==1)  
			y=y-x;  // because X Half a minute after birth Y, After every 1 Minutes to eat Y, So it is always an odd number of half minutes to eat Y
			
		if(t%4==0)  // Double every two minutes  
			y=y*2;
			
		if(t%6==0)  // Double every three minutes 
			x=x*2;
	} 
	printf("%d",y);
	return 0;
 } 

The running result is negative , so y=0.

When X=10, Y=90, Running results ：