Exercise 8-10 output student grades (20 points)

This question requires the preparation of procedures , According to the input student's score , Count and output the average score of students 、 Top and bottom . Dynamic memory allocation is recommended for .

Input format ：

Enter the first line to first give a positive integer N, Number of students . The next line shows N Results of students , Numbers are separated by spaces .

Output format ：

Output in the following format ：

average =  Average score 
max =  Top grade 
min =  Minimum score 

Keep two decimal places for results .

sample input ：

3
85 90 95

sample output ：

average = 90.00
max = 95.00
min = 85.00

The code is as follows ：

#include<stdio.h>
#include<stdlib.h>
int main()
{
    double max=0,min=0,sum=0;
    double average=0;
    int n,i;
    scanf("%d",&n);
    double a[n];
    //double *ave= (double *)malloc( n* sizeof(double)); Dynamic memory allocation application 
    for(i=0;i<n;i++){
        scanf("%lf",&a[i]);
    }
     max=min=a[0];
    for(i=0;i<n;i++){
        sum+=a[i];
        if(a[i]>max){
            max=a[i];
        }
        if(a[i]<min){
            min=a[i];
                     }
    }
    printf("average = %.2f\n",sum/n);
    printf("max = %.2f\n",max);
    printf("min = %.2f\n",min);
    //free(0); Release space 
    return 0;
}