7-3 count the number of words in a line of text

This topic requests to write a program to count the number of words in a line of characters . So-called “ word ” A string that has no spaces in it , Separate the words with spaces , The number of spaces can be multiple .

Input format :

Type to give a line of characters .

Output format :

Output the number of words in a line .

sample input :

Let's go to room 209.

sample output :

5

  Ideas ： I originally wanted to count letters, but I saw that the required string on the topic was a string without spaces , in other words &*, This kind of strange characters , If you use something that is not a space, it is c!=' ', But if it is a blank space, you have to count , So let's look at the blanks , If the first letter appears after a space, it is a string , At the beginning, there was no ‘ ’, But it's also a string . Let's define a flag after the space appears , Let this sign become 1, The next time we encounter something that is not a space, we will add the count variable 1, Add in the count variable 1 Then let's change the space mark 0, As for the first part without spaces, it is also a string , We just need to make the logo initial 1 that will do , According to this idea, we write the following code .

Code ：

#include <stdio.h>
#include <string.h>
int main(){
    int number=0;
    int i,flag=1;
    char a[10000];
    gets(a);
    int len=strlen(a);
    for(i=0;i<len;i++){
        if(a[i]==' ')flag=1;
        if(a[i]!=' '&&flag==1){
            number++;
            flag=0;
        }
    }
    printf("%d",number);
}