Exercise 6-1 classify and count the number of characters

exercises 6-1 Classify and count the number of characters (15 branch )

This question requests to realize a function , Statistics of Chinese and English letters in a given string 、 Space or enter 、 The number of numeric characters and other characters .

Function interface definition ：

void StringCount( char s[] );

among  char s[]  Is the string passed in by the user . function StringCount Must be in one line according to

letter =  The number of English letters , blank =  The number of spaces or carriage returns , digit =  Number of characters , other =  The number of other characters 

Format output .

Sample referee test procedure ：

#include <stdio.h>
#define MAXS 15

void StringCount( char s[] );
void ReadString( char s[] ); /*  By the referee , Omit no watch  */

int main()
{
    char s[MAXS];

    ReadString(s);
    StringCount(s);

    return 0;
}

/* Your function will be put here */

sample input ：

aZ &
09 Az

sample output ：

letter = 4, blank = 3, digit = 2, other = 1

void StringCount(char s[]){
    int letter=0,blank=0,digit=0,other=0,i=0;
    do{
        if(s[i]>='a'&&s[i]<='z'||s[i]>='A'&&s[i]<='Z'){
            letter++;
        }else if(s[i]==' '||s[i]=='\n'){
            blank++;
        }else if (s[i] >= '0' && s[i] <= '9'){
            digit++;
        }else{
            other++;
        }
        i++;
    }while(s[i]!='\0');
    printf("letter = %d, blank = %d, digit = %d, other = %d", letter, blank, digit, other);
}