Flask project uses flask socketio exception: typeerror: function() argument 1 must be code, not str

Use it directly pip To install ：

pip install flask-socketio

Wrote a Demo：

from flask import Flask, render_template
from flask_socketio import SocketIO

app = Flask(__name__)
app.config['SECRET_KEY'] = 'secret!'
socketio = SocketIO(app)

if __name__ == '__main__':
    socketio.run(app, host='0.0.0.0', debug=True)

  The result is wrong ：

TypeError: function() argument 1 must be code, not str

As a result, the problem ：

Confirmed working after upgrading Python package aiohttp from version 3.7.4 to 3.8.1.

For confirmation aiohttp Version is too low , yes 3.6.1 Of , So I upgraded ：

pip install --upgrade aiohttp

Then it can be started normally ：