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Bernoulli distribution (a discrete distribution)
2022-07-01 18:23:00 【Uncertainty!!】
Bernoulli distribution
Note source :Introduction to the Bernoulli Distribution
Bernoulli distribution binomial distribution (n Experiments ) The special case of , One experiment was carried out ( n = 1 n=1 n=1) The result of each experiment is only successful / Failure , It is also a special case of two-point distribution , The possible result need not be 0 and 1
Screenshot of the source :Bernoulli distribution
The following figure shows three examples of Bernoulli distribution 




x = 0 , 1 x=0,1 x=0,1
P ( X = 0 ) = p 0 ( 1 − p ) 1 − 0 = 1 − p P ( X = 1 ) = p 1 ( 1 − p ) 1 − 1 = p P(X=0)=p^0(1-p)^{1-0}=1-p\\ ~\\ P(X=1)=p^1(1-p)^{1-1}=p P(X=0)=p0(1−p)1−0=1−p P(X=1)=p1(1−p)1−1=p
mean value 
variance 

Example :

The probability of randomly selecting a lawyer p = 1 200 The probability of randomly selecting a person who is not a lawyer p = 1 − 1 200 = 199 200 P ( X = x ) = ( 1 200 ) x ( 1 − 1 200 ) 1 − x for x=0,1 P ( X = 0 ) = ( 1 200 ) 0 ( 1 − 1 200 ) 1 − 0 = 199 200 P ( X = 1 ) = ( 1 200 ) 1 ( 1 − 1 200 ) 1 − 1 = 1 200 \text{ The probability of randomly selecting a lawyer }\ p=\frac{1}{200}\\ ~\\ \text{ The probability of randomly selecting a person who is not a lawyer }\ p=1-\frac{1}{200}=\frac{199}{200}\\ ~\\ P(X=x)=(\frac{1}{200})^x(1-\frac{1}{200})^{1-x}\\ ~\\ \text{for\ x=0,1}\\ ~\\ P(X=0)=(\frac{1}{200})^0(1-\frac{1}{200})^{1-0}=\frac{199}{200}\\ ~\\ P(X=1)=(\frac{1}{200})^1(1-\frac{1}{200})^{1-1}=\frac{1}{200} The probability of randomly selecting a lawyer p=2001 The probability of randomly selecting a person who is not a lawyer p=1−2001=200199 P(X=x)=(2001)x(1−2001)1−x for x=0,1 P(X=0)=(2001)0(1−2001)1−0=200199 P(X=1)=(2001)1(1−2001)1−1=2001
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