Leetcode simple question: check whether two string arrays are equal

subject

Here are two string arrays word1 and word2 . If two arrays represent the same string , return true ; otherwise , return false .
Array representation string Is made up of all the elements in the array According to the order The string formed by the connection .
Example 1：
Input ：word1 = [“ab”, “c”], word2 = [“a”, “bc”]
Output ：true
explain ：
word1 The string represented is “ab” + “c” -> “abc”
word2 The string represented is “a” + “bc” -> “abc”
The two strings are the same , return true
Example 2：
Input ：word1 = [“a”, “cb”], word2 = [“ab”, “c”]
Output ：false
Example 3：
Input ：word1 = [“abc”, “d”, “defg”], word2 = [“abcddefg”]
Output ：true
Tips ：
1 <= word1.length, word2.length <= 10^3
1 <= word1[i].length, word2[i].length <= 10^3
1 <= sum(word1[i].length), sum(word2[i].length) <= 10^3
word1[i] and word2[i] It's made up of lowercase letters
source ： Power button （LeetCode）

Their thinking

   The simplest way to solve this problem is to splice the elements in the array into sentences, and then compare whether the sentences are equal .

class Solution:
    def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool:
        return ''.join(word1)==''.join(word2)

   Of course, you can also traverse characters one by one .

class Solution:
    def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool:
        i=0
        j=0
        A=iter(word1[i])
        B=iter(word2[i])
        while True:
            try:
                s1=next(A)
            except:
                i+=1
                if i==len(word1):
                    break
                A=iter(word1[i])
                s1=next(A)
            try:
                s2=next(B)
            except:
                j+=1
                if j==len(word2):
                    break
                B=iter(word2[j])
                s2=next(B)
            if s1!=s2:
                return False
        try:
            next(A)
            return False
        except:
            try:
                iter(word1[i+1])
                return False
            except:
                pass
        try:
            next(B)
            return False
        except:
            try:
                iter(word2[j+1])
                return False
            except:
                pass
        return True if s1==s2 else False