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leetcode:面试题 17.24. 子矩阵最大累加和(待研究)
2022-07-06 21:04:00 【游戏编程】
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1 <= matrix.length, matrix[0].length <= 200
: 1 0 8 / 1 0 2 = 1 0 6 , ( 1 0 2 ) 3 = 1 0 6 10^8 / 10^2 = 10^6,(10^2)^3 = 10^6 108/102=106,(102)3=106,所以算法最大时间复杂度是 O ( N 3 ) O(N^3) O(N3),可以用dp来做
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