当前位置:网站首页>The use of list and Its Simulation Implementation
The use of list and Its Simulation Implementation
2022-07-07 11:06:00 【Exy-】
One .list iterator Use
int ar[] = { 1,2,3,4,5,6,7,8,9,0 };
int n = sizeof(ar) / sizeof(ar[0]);
//list<int> mylist(10,5);// Two way circular list with leading node
list<int> mylist(ar, ar + n);
for (const auto& e : mylist)
{
cout << e << " ";
}
cout << endl;
list<int>::iterator it = mylist.begin();
while (it != mylist.end())
{
cout << *it << " ";
++it;
}
cout << endl;
list<int>::reverse_iterator rit = mylist.rbegin();
while (rit != mylist.rend())
{
cout << *rit << " ";
++rit;
}
cout << endl;
3.list Iterator failure problem for
Two .list Built in functions for
list<int> mylist;
mylist.empty testing list Is it empty , Is to return true, Otherwise return to false
mylist.size return list Number of valid nodes in
mylist.front return list The reference to the value in the first node of
mylist.back return list Reference to the value of the last node of
3、 ... and .list Simulation Implementation
namespace ljx
{
template<class T>
struct __list_node
{
__list_node<T>* _next;
__list_node<T>* _prev;
T _data;
__list_node(const T& x=T())
:_data(x)
,_next(nullptr)
,_prev(nullptr)
{}
};
template<class T,class Ref,class Ptr>
struct __list_iterator
{
typedef __list_node<T>node;
typedef __list_iterator<T, Ref, Ptr>Self;
node* _node;
__list_iterator(node* node)
:_node(node)
{}
T* operator->()
{
return &_node->_data;
}
T& operator*()
{
return _node->_data;
}
Self& operator++()
{
_node = _node->_next;
return *this;
}
Self& operator++(int)
{
Self tmp(*this);
//_node = _node->_next;
++(*this);
return tmp;
}
Self& operator--()
{
_node = _node->_prev;
return *this;
}
Self& operator--(int)
{
__list_iterator<T>tmp(*this);
--(*this);
return tmp;
}
bool operator!=(const Self& it)
{
return _node != it._node;
}
bool operator==(const Self& it)
{
return _node == it._node;
}
};
template<class T>
class list
{
typedef __list_node<T> node;
public:
typedef __list_iterator<T, T&, T*>iterator;
typedef __list_iterator<T,const T&,const T*> const_iterator;
// Take the lead in two-way circular list
//typedef __list_iterator<T,const T&,const T * > const_iterator;
iterator begin()
{
return iterator(_head->_next);
}
const_iterator begin()const
{
return const_iterator(_head->_next);
}
iterator end()
{
return iterator(_head);
}
const_iterator end()const
{
return const_iterator(_head);
}
list()
{
_head = new node;
_head->_next = _head;
_head->_prev = _head;
}
list(const list<T>& lt)
{
_head = new node;
_head->_next = _head;
_head->_prev = _head;
//const_iterator it = lt.begin();
//while (it != lt.end())
//{
// push_back(*it);
// ++it;
//}
for (auto e : lt)
{
push_back(e);
}
}
//list <T>& operator=(const list<T>& lt)
//{
// if (this != <)
// {
// clear();
// for (auto e : lt)
// {
// push_back(e);
// }
// }
// return *this;
//}
list<T>& operator=(list<T> lt)
{
swap(_head, lt._head)
return *this;
}
~list()
{
clear();
delete _head;
_head = nullptr;
}
void clear()
{
node* p = _head->_next;
while (p != _head)
{
delete(p);
}
}
void push_back(const T& x)
{
//node* tail = _head->_prev;
//node* newnode = new node(x);
//tail->_next = newnode;
//newnode->_prev = tail;
//newnode->_next = _head;
//_head->_prev = newnode;
insert(end(), x);
}
void push_front(const T& x);
void insert(iterator pos, const T& x)
{
node* cur = pos._node;
node* prev = cur->_prev;
node* newnode = new node(x);
prev->_next = newnode;
newnode->_prev = prev;
newnode->_next = cur;
cur->_prev = newnode;
}
void erase(iterator pos)
{
assert(pos != end());
{
node* cur = pos._node;
node* prev = cur->_prev;
node* next = cur->_next;
delete cur;
prev->_next = next;
next->_prev = prev;
}
}
void pop_back()
{
erase(iterator(_head->_prev));
erase(--end());
}
private:
node* _head;
};
}
边栏推荐
- Mysql的json格式查询
- IDEA快捷键大全
- "Dream Cup" 2017 Jiangsu information and future primary school summer camp it expert PK program design questions
- 从色情直播到直播电商
- Static semantic check of clang tidy in cicd
- A case of compiling QT file qmake compiling script
- Go-Redis 中间件
- Typescript interface inheritance
- Those confusing concepts (3): function and class
- Unity websocket server
猜你喜欢
中级软件评测师考什么
1321: [example 6.3] deletion problem (noip1994)
Online hard core tools
[STM32] actual combat 3.1 - drive 42 stepper motors with STM32 and tb6600 drivers (I)
July 10, 2022 "five heart public welfare" activity notice + registration entry (two-dimensional code)
Still cannot find RPC dispatcher table failed to connect in virtual KD
2022年7月10日“五心公益”活动通知+报名入口(二维码)
【安装系统】U盘安装系统教程,使用UltraISO制作U盘启动盘
Find the root of equation ax^2+bx+c=0 (C language)
简单易修改的弹框组件
随机推荐
Cmake learning manual
Go-Redis 中间件
Applet jump to H5, configure business domain name experience tutorial
变量的解构赋值
打算参加安全方面工作,信息安全工程师怎么样,软考考试需要怎么准备?
The fifth training assignment
[untitled]
2021-04-23
如何顺利通过下半年的高级系统架构设计师?
How to get hardware information in unity
软考中级,软件设计师考试那些内容,考试大纲什么的?
The seventh training assignment
Mysql的json格式查询
一些线上学术报告网站与机器学习视频
中级网络工程师是什么?主要是考什么,有什么用?
2022.7.5DAY597
Basic introduction of yarn and job submission process
Network engineer test questions and answers in May of the first half of 2022
Introduction to shell programming
A simple example of delegate usage