SQL function SQRT

A numeric function that returns the square root of a given numeric expression.

Outline

SQRT(numeric-expression){fn SQRT(numeric-expression)}

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parameter

• numeric-expression - An expression that resolves to a positive number that computes the square root.

SQRT returns NUMERIC or DOUBLE data types.SQRT returns DOUBLE if numeric-expression is of data type DOUBLE; otherwise, it returns NUMERIC.

Description

SQRT Returns the square root of numeric-expression.numeric-expression must be a positive number.Negative numeric expressions (except -0) generate SQLCODE -400 errors.If a NULL value is passed, SQRT returns NULL.

SQRT returns a value with a precision of 36 and a scale of 18.

SQRT can be specified as a regular scalar function or as a ODBC scalar function (using curly brace syntax).

Example

The following examples show two forms of SQRT syntax.Both return the square root of 49:

SELECT SQRT(49) AS SRoot,{fn SQRT(49)} AS ODBCSRoot7 7

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The following embedded SQL example returns the square root of the integer 0 to 10:

/// d ##class(PHA.TEST.SQLFunction).Sort()ClassMethod Sort(){s a = 0while a < 11 {&sql(SELECT SQRT(:a) INTO :b)if SQLCODE '= 0 {w !,"Error code ",SQLCODE} else {w !,"The square root of ",a," = ",bs a = a + 1}}}

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DHC-APP>d ##class(PHA.TEST.SQLFunction).Sort()The square root of 0 = 0The square root of 1 = 1The square root of 2 = 1.414213562373095049The square root of 3 = 1.732050807568877294The square root of 4 = 2The square root of 5 = 2.236067977499789697The square root of 6 = 2.449489742783178098The square root of 7 = 2.645751311064590591The square root of 8 = 2.828427124746190098The square root of 9 = 3The square root of 10 = 3.162277660168379332

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