当前位置:网站首页>1. Circular nesting and understanding of lists
1. Circular nesting and understanding of lists
2022-07-04 10:38:00 【She was your flaw】
1. The implementation principle of loop nesting : External circulation once , Complete internal circulation
for x in range(5):
for y in range(2, 5):
print(x, y)
x Value range :0,1,2,3,4
The first 1 Time x=0: Execute the corresponding for loop , y The value range is : 2,3,4
The first 1 Time y=2: print(x, y) -> print(0, 2)
The first 2 Time y=3: print(x, y) -> print(0, 3)
The first 3 Time y=4: print(x, y) -> print(0, 4)
End of internal circulation
The first 2 Time x=1: Execute the corresponding for loop , y The value range is : 2,3,4
The first 1 Time y=2: print(x, y) -> print(1, 2)
The first 2 Time y=3: print(x, y) -> print(1, 3)
The first 3 Time y=4: print(x, y) -> print(1, 4)
End of internal circulation
2. What is a list (list)
1) A list is a container data type ( Sequence ), take []z As a sign of the container , Multiple elements are separated by commas :[ Elements 1, Elements 2, Elements 3,...]
2) The list is variable ( Number of elements 、 Values and order are variable ) - increase 、 Delete 、 Change ; The list is ordered - Subscript operation is supported
3) List requirements for elements : No requirement ( No matter what type of data can be used as elements of the list )
'''
1) An empty list
list1 = []
list2 = [ ]
print(type(list1), type(list2)) # <class 'list'> <class 'list'>
print(bool(list1), bool(list2)) # False False
print(len(list1), len(list2)) # 0 0
2) The list can save multiple data at the same time
list3 = [89, 90, 76, 99, 58]
print(list3)
list4 = [' Tan ', 3, 100, True]
print(list4)
3. check - Get elements
There are three situations : Get a single element 、 section 、 Traverse ( One by one )
1) Get a single element
grammar : list [ Subscript ]
function : Get the element corresponding to the specified subscript in the list
explain :
list - Any expression that results in a list , such as : Save the variables of the list 、 Specific list values, etc
[] - Fixed writing
Subscript - A subscript is also called an index , Is the position information of elements in an ordered sequence .
python Each element in the ordered sequence in has two sets of subscript values , Namely : From front to back 0 The subscript value that starts to increment ; From back to front -1 Subscript value that begins to decrease
Be careful : Subscript cannot be out of bounds
list3 = [89, 90, 76, 99, 58]
list3[ Subscript ]
[89, 90, 76, 99, 58][ Subscript ]
names = [' Diana Spencer ', ' Childcare cord ', ' Primary school hate ', ' Obama ', ' Kalma ', ' Laches ']
print(names[0]) # Diana Spencer
print(names[-1]) # Laches
print(names[-2]) # Kalma
print(names[-5]) # Childcare cord
print(names[10]) # Report errors
2) Traverse
The way 1 - Get each element in the list directly
for Variable in list :
The loop body
The way 2 - First get the subscript value of each element , Then get the element by subscript
for Subscript in range(len( list )):
The loop body
for Subscript in range(-1, -len( list )-1, -1):
The loop body
range(len( list )) == range( The number of elements in the list )
The way 3 - At the same time, get the subscript corresponding to each element in the list
for Subscript , Elements in enumerate( list ):
The loop body
print('---------------- Gorgeous divider --------------')
for index in range(len(names)):
print(index, names[index])
print('---------------- Gorgeous divider --------------')
for index, item in enumerate(names):
print(index, item)
practice 1: Count the number of people who failed
scores = [89, 67, 56, 90, 98, 30, 78, 51, 99]
count = 0
for x in scores:
if x < 60:
count += 1
print(' The number of failures :', count)
practice 2: Count the number of integers in the list
list7 = [89, 9.9, 'abc', True, 'abc', '10', 81, 90, 23]
count = 0
for x in list7:
if type(x) == int:
count += 1
print(count)
practice 3: seek nums The sum of all even numbers in
nums = [89, 67, 56, 90, 98, 30, 78, 51, 99]
sum1 = 0
for x in nums:
if x % 2 == 0:
sum1 += x
print(' The sum of all even numbers :', sum1)
4. increase - Additive elements
- Add a single element
list .append( Elements ) - Add an element at the end of the list
list .insert( Subscript , Elements ) - Inserts the specified element before the element corresponding to the specified subscript
movies = [' Fifty six degrees grey ', ' Godzilla vs. King Kong ', ' Peach blossom Man vs chrysanthemum monster ']
print(movies) # [' Fifty six degrees grey ', ' Godzilla vs. King Kong ', ' Peach blossom Man vs chrysanthemum monster ']
movies.append(' Shawshank's salvation ')
print(movies) # [' Fifty six degrees grey ', ' Godzilla vs. King Kong ', ' Peach blossom Man vs chrysanthemum monster ', ' Shawshank's salvation ']
movies.insert(2, ' Silent lamb ')
print(movies) # [' Fifty six degrees grey ', ' Godzilla vs. King Kong ', ' Silent lamb ', ' Peach blossom Man vs chrysanthemum monster ', ' Shawshank's salvation ']
2) Batch addition
list 1.extend( list 2) - Will list 2 All elements are added to the list 1 Behind
movies.extend([' Let the bullets fly ', ' Touch and ', 'V For vendetta '])
print(movies) # [' Fifty six degrees grey ', ' Godzilla vs. King Kong ', ' Silent lamb ', ' Peach blossom Man vs chrysanthemum monster ', ' Shawshank's salvation ', ' Let the bullets fly ', ' Touch and ', 'V For vendetta ']
practice : take scores Extract all the passing scores in
scores = [89, 67, 56, 90, 98, 30, 78, 51, 99]
scores2 = []
for x in scores:
if x >= 60:
scores2.append(x)
print(scores2)
First week homework
One 、 choice question
In the following variable names illegal Yes. ?(C)
A. abc
B. Npc
C. 1name
D ab_cd
In the following options Do not belong to The key word is ?(B)
A. and
B. print
C. True
D. in
Which of the following options corresponds to the correct code writing ?(C)
A.
print('Python') print(' Novice Village ') # Incorrect indentationB.
print('Python') print(' Novice Village ') # useless , separateC.
print('Python') print(' Novice Village ')D.
print('Python'' Novice Village ') # String is useless , separateThe following options can print 50 Yes. ?(B)
A.
print('100 - 50') # 100-50B.
print(100 - 50)About Quotes , The correct choice used in the following options is ?(D)
A.
print('hello)B.
print("hello')C.
print(“hello”)D.
print("hello")
Two 、 Programming questions
Write code and print on the console
good good study, day day up!a = 'good good study,day day up!' print(a)Write code and print on the console 5 Time
you see see, one day day!a = 'you see see, one day day!' b = 5 while b > 0: print(a) b -= 1Write code, print numbers 11、12、13、… 21
for x in range (11, 22): print(x)Write code, print numbers 11,13,15,17,…99
for x in range (11, 100, 2): print(x)Write code, print numbers :10、9、8、7、6、5
for x in range(10, 4, -1): print(x)Write code calculation :1+2+3+4+…+20 And
sum1 = 0for x in range(1, 21): sum1 += xprint(sum1) # 210Write code calculation 100 The sum of all even numbers within
sum2 = 0for x in range(2, 100, 2): sum2 += x print(sum2) # 2450Write code statistics 100~200 The median is 3 The number of
a = 0for x in range(103, 201, 10): a += 1 print(a) # 10Write code calculation
2*3*4*5*...*9Resultb = 1 for x in range(2, 10): b *= x print(b) # 362880Enter a number , If the number entered is even, print
even numbersOtherwise printOdd numberc = int(input(' Please enter :')) if c % 2 == 0: print(' even numbers ') else: print(' Odd number ')Statistics 1000 Endogenic quilt 3 Divisible but not by 5 The number of integers .
d = 0 for x in range(0, 1000, 3): if x % 5 != 0: d += 1 print(d) # 267
边栏推荐
- leetcode729. My schedule 1
- 【FAQ】华为帐号服务报错 907135701的常见原因总结和解决方法
- Hlk-w801wifi connection
- Does any teacher know how to inherit richsourcefunction custom reading Mysql to do increment?
- System. Currenttimemillis() and system Nanotime (), which is faster? Don't use it wrong!
- Article publishing experiment
- Rhcsa day 9
- [machine] [server] Taishan 200
- Rhcsa day 10 operation
- Container cloud notes
猜你喜欢

Rhcsa day 9

Rhcsa day 10 operation

Static comprehensive experiment ---hcip1
![[test theory] test process management](/img/d2/65865dffacf38d9a8be720868b75f0.jpg)
[test theory] test process management

DML statement of MySQL Foundation

leetcode1-3

Rhcsa learning practice

Today's sleep quality record 78 points

Reprint: summation formula of proportional series and its derivation process

When I forget how to write SQL, I
随机推荐
按键精灵打怪学习-识别所在地图、跑图、进入帮派识别NPC
DNS hijacking
RHCE - day one
Map container
OSPF comprehensive experiment
Student achievement management system (C language)
Rhcsa day 9
[Galaxy Kirin V10] [server] system partition expansion
If the uniapp is less than 1000, it will be displayed according to the original number. If the number exceeds 1000, it will be converted into 10w+ 1.3k+ display
Basic principle of servlet and application of common API methods
Latex learning insertion number - list of filled dots, bars, numbers
Rhsca day 11 operation
Legion is a network penetration tool
Occasional pit compiled by idea
Collection of practical string functions
Write a program to judge whether the elements contained in a vector < int> container are 9.20: exactly the same as those in a list < int> container.
[testing theory] thinking about testing profession
[Galaxy Kirin V10] [server] failed to start the network
Recursion and divide and conquer strategy
The future education examination system cannot answer questions, and there is no response after clicking on the options, and the answers will not be recorded