Haut OJ 1401: praise energy

Problem description ：

  Tao Bao Liang 11 give the thumbs-up PK Energy gathering was very hot at that time . Just a few days. , Someone knows the secret of win-win cooperation , There are also people who fight in order to cheat praise , A lot of time was wasted for a little money . But anyway , Finally, it's time to divide up the energy of the team . The energy shared by each person is the number of likes that person has contributed to the team （ Proportion of the whole team ） In direct proportion to , The more you contribute , The more energy you get . Suppose a team has 5 personal .

Input ：

The first line is the total energy integer of the team n（100<=n<=100000）
The first 2~6 Line is everyone The number of likes contributed to the team x. （0<= x <= 100000)

Output ：

Output takes up one line , Output the energy shared by everyone separately （ Rounding down ）, Space separates the middle

The sample input ：

8000
50
30
10
10
0

Sample output ：

4000 2400 800 800 0

Tips ：

If two people contribute equal praise , Then they share the same energy value .

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Cause analysis ：

1. Be careful All contributions 0 The situation of Then divide equally .

2. Contribution points given in the example , Not by pressing 100% Calculated , Just contribute , Just give exactly equal to 100.

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Solution ：

#include<stdio.h>
#include<math.h>

int main()
{
    int n,a[6],s=0,b[6];
    int i;
    scanf("%d",&n);
    for(i=1;i<=5;i++)
    {
        scanf("%d",&a[i]);
        s+=a[i];
    }
    if(s==0)
        for(i=1;i<=5;i++)
        b[i]=n/5;
    else
        for(i=1;i<=5;i++)
        b[i]=n*(a[i]*1.0/s);
    for(i=1;i<=5;i++)
        printf("%d ",b[i]);
}