L1-025 positive integer a+b (15 points)

L1-025 Positive integer A+B (15 branch )

The goal of the question is very simple , It's two positive integers A and B And , among A and B It's all in the range [1,1000]. A little bit of a hassle , The input is not guaranteed to be two positive integers .

Input format ：
Type in on a line to give A and B, They are separated by spaces . The problem is A and B It doesn't have to be a positive integer , Sometimes it can be out of range numbers 、 negative 、 A real number with a decimal point 、 It's even a mess of code .

Be careful ： Let's put... In the input 1 A space is taken as A and B Separation of . Make sure that there is at least one space for the question , also B It's not an empty string .

Output format ：
If the input is really two positive integers , According to the format A + B = and Output . If an input is not satisfactory , Output at corresponding position ?, Obviously at this time and also ?.

sample input 1：

123 456

sample output 1：

123 + 456 = 579

sample input 2：

22. 18

sample output 2：

? + 18 = ?

sample input 3：

-100 blabla bla...33

sample output 3：

? + ? = ?

test 3： Similar to the third example , There may be more than two data entered , When the input data exceeds two data , You should directly output the results that are all question marks

test 5： The upper limit of the number is 1000, There are requirements for the topic , But when typing , I didn't input as required, so I need to judge
test 6： The lower limit of the number is 1, And testing 5 identical

AC Code

#include<iostream>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<vector>
#include<stack>
#include<queue>
#include<sstream>

using namespace std;
typedef long long ll;
const int N=100010;

int main()
{
    
	string a;
	getline(cin, a);
	bool flaga = false, flagb = false;
	int aa = 0, bb = 0;
	int flag = 0;
	for(int i = 0; i < a.size(); i ++ )
	{
    
		if(a[i] == ' ') flag = i;
		if(flag > 0) break;
	}
	for(int i = 0; i < flag; i ++ )
	{
    
		aa = aa * 10 + (a[i] - '0');
		if(a[i] < '0' || a[i] > '9')
		{
    
			flaga = true;
			break;
		}
	}
	int flag1 = 0;
	for(int i = flag + 1; i < a.size(); i ++ )
	{
    
		bb = bb * 10 + (a[i] - '0');
		if(a[i] < '0' || a[i] > '9')
		{
    
			flagb = true;
			break;
		}
	}
	if(aa > 1000 || aa < 1) flaga = true;
	if(bb > 1000 || bb < 1) flagb = true;
	if(flaga) cout << '?' << ' ';
	else cout << aa << ' ';
	cout << '+' << ' ';
	if(flagb) cout << '?' << ' ';
	else cout << bb << ' ';
	cout << '=' << ' ';
	if(flaga || flagb) cout << '?';
	else cout << aa + bb;
	return 0;
}