Finishing (III) - Exercise 2

1、 Enter some positive integers （≤26）, Program to output the letter triangle attached to the wall with these positive integers as the side length .

#include <iostream>
#include <cstdio>
using namespace std;
 
int main()
{
    int n,i,j;
    while(cin>>n)
    {
        char a;
        for(i=1;i<=n;i++)
        {
            cout<<"a";
            for(j=1;j<=n-i;j++)
                {cout<<" ";}
            char a=97;
            for(j=1;j<=i;j++)
            {cout<<char(a+j-1);}
            cout<<endl;
        }
        cout<<endl;
    }
    return 0;
}

Input ：
3
7
Output ：
a  a
a ab
aabc

a      a
a     ab
a    abc
a   abcd
a  abcde
a abcdef
aabcdefg

 2、 Xiao Jin plays cards , When the number of cards in the other party's hand is greater than or equal to 10 Zhang Shi , He will observe each other's expression , If the other party looks nervous , He's out “ Fried ”, If the other party is laughing , He doesn't play any cards .
character 'J' Express that the other party is nervous about applying ,'H' Express that the other party is laughing . Xiao Jinchu “ Fried ”, The output “Z”, If you don't play any cards , The output “pass”.
When the number of cards in the other hand is less than 10 Zhang's time , He will “ Pick up ” The other side's card , That is, the other party goes out “ single ”, He also came out “ single ”, The other party “ double ”, He also made a double .
character 'D’ On behalf of the other party “ single ”,'S' On behalf of the other party “ double ”. Xiao Jinchu “ single ”, The output “D”, If it comes out “ double ”, The output “S”.

#include<iostream>
using namespace std;
int main()
{
    int n;char b,c;
    cin>>n>>b>>c;
    if(n>=10)
    {
        if(b=='J') cout<<"Z";
        if(b=='H') cout<<"pass";
    }
    if(n<10)
    {
        if(c=='D') cout<<"D";
        if(c=='S') cout<<"S";
    }
}

Input 1：
15 H D
Input 2：
9 J S
Output 1：
pass
Output 2：
S

3、  A hundred dollars for a hundred chickens ： A chicken is worth five , A hen is worth three , A chicken is worth three , A hundred dollars for a hundred chickens , Ask jiweng 、 mother 、 How much is it ？

#include<iostream>
using namespace std;
int main()
{
 for (int a = 0; a <= 20; a++)
  
   for (int b = 0; b <= 33; b++)
    
     for (int c = 0; c <= 100 - a - b; c = c + 3)
        
          if ((a + b + c == 100) and (5 * a + 3 * b + c / 3 == 100))
             
           cout << a << " "<<b<<" " << c;
}