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20220601 Mathematics: zero after factorial
2022-07-03 10:11:00 【Seeyouagain】
Title Description : Given an integer n , return n! The number of trailing zeros in the result . Tips n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1.
coded :
public int trailingZeroes(int n) {
int result = 0;
while (n >= 5){
result += n/5;
n /= 5;
}
return result;
}
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