Force buckle 4_ 412. Fizz Buzz

Give you an integer n , Find out from 1 To n Of each integer Fizz Buzz Express , And use string array answer（ Subscript from 1 Start ） Return results , among ：

answer[i] == "FizzBuzz"  If  i  At the same time  3  and  5  Multiple .
answer[i] == "Fizz"  If  i  yes  3  Multiple .
answer[i] == "Buzz"  If  i  yes  5  Multiple .
answer[i] == i （ In string form ） If none of the above conditions are met .

Example 1：

 Input ：n = 3
 Output ：["1","2","Fizz"]

Example 2：

 Input ：n = 5
 Output ：["1","2","Fizz","4","Buzz"]

Example 3：

 Input ：n = 15
 Output ：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

source ： Power button （LeetCode）

Java solution

class Solution {
    
    public List<String> fizzBuzz(int n) {
    
        List<String> lst = new ArrayList<String>();
        for (int i = 0; i < n; i++) {
    
            int num = i + 1;
            if (num % 3 == 0 && num % 5 == 0) lst.add("FizzBuzz");
            else if (num % 3 == 0) lst.add("Fizz");
            else if (num % 5 == 0) lst.add("Buzz");
            else lst.add(String.valueOf(num));
            //String.valueOf(num) take num Convert to string 
        }
        return lst;
    }
}

Python solution

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        ans = []
        for i in range(1, n + 1):
            s = ""
            if i % 3 == 0:
                s += "Fizz"
            if i % 5 == 0:
                s += "Buzz"
            if s == "":
                s = str(i)
            ans.append(s)
        return ans